tiflolinux.org - GNU Social
  • Login

Bienvenido

  • Public

    • Public
    • Network
    • Groups
    • Popular
    • People

Conversation

Notices

  1. spectrumgomas@functional.cafe's status on Thursday, 03-Jun-2021 16:19:51 CEST spectrumgomas spectrumgomas

    https://en.wikipedia.org/wiki/Malfatti_circlesIn the picture, if the radius of each circle is 4 cm, can anyone tell me how long is the side of the equilateral triangle?

    In conversation Thursday, 03-Jun-2021 16:19:51 CEST from functional.cafe permalink

    Attachments


    1. https://functional.cafe/system/media_attachments/files/106/347/229/713/168/606/original/f4f60accf5990800.png
    • Elias Mårtenson (loke@functional.cafe)'s status on Thursday, 03-Jun-2021 20:25:51 CEST Elias Mårtenson Elias Mårtenson
      in reply to

      @spectrumgomas well I'd take the tangent of the line, and since I know the angle I can then compute the intersection point and from there easily calculate the side length. Now, I'm on my phone right now so I'm not going to actually solve it.

      Anyway, I'm sure there is some clever solution that doesn't require trigonometry?

      In conversation Thursday, 03-Jun-2021 20:25:51 CEST permalink
    • spectrumgomas@functional.cafe's status on Thursday, 03-Jun-2021 22:15:00 CEST spectrumgomas spectrumgomas
      in reply to
      • Elias Mårtenson
      • Thomas

      @loke @tfb I don't see it. tag 60 = sqr(3) = h / (l/2) -> l = 2h/(sqr 3) , but it isn't related with the radius of the circles.

      In conversation Thursday, 03-Jun-2021 22:15:00 CEST permalink

Feeds

  • Activity Streams
  • RSS 2.0
  • Atom
  • Help
  • About
  • FAQ
  • TOS
  • Privacy
  • Source
  • Version
  • Contact

tiflolinux.org - GNU Social is a social network, courtesy of tiflolinux.org. It runs on GNU social, version 2.0.1-beta0, available under the GNU Affero General Public License.

Creative Commons Attribution 3.0 All tiflolinux.org - GNU Social content and data are available under the Creative Commons Attribution 3.0 license.